Answered

A pool can be filled by one particular pipe in 10 hours, whereas a different pipe requires 6 hours to fill the same pool. How long would it take to fill the pool with both pipes turned on?

Answer :

In one hour the first pipe fills 1/10 of total.

In one hour the second pipe fills 1/6 of total.

One hour with both pipes turned on fills:

[tex]\frac{1}{10}+\frac{1}{6}=\frac{16}{60}=\frac{8}{30}=\frac{4}{15}[/tex]

fills 4/15 on one hour, then to fully fill the pool with both pipes turned on we need:

[tex]\frac{1}{\frac{4}{15}}=\frac{15}{4}=3.75[/tex]

3 hours and 45 minutes.

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