Answer :
Answer:
The area of the triangle is;
[tex]43.3\text{ square ft}[/tex]Explanation:
Given an equilateral triangle with sides 10ft.
Recall that the area of a triangle can be calculated using the formula;
[tex]A=\frac{1}{2}bh[/tex]The height of the triangle would be;
[tex]\begin{gathered} h=\sqrt[]{10^2-5^2} \\ h=\sqrt[]{75}^{} \\ h=5\sqrt[]{3} \end{gathered}[/tex]and the base length is;
[tex]b=10[/tex]substituting;
[tex]\begin{gathered} A=\frac{1}{2}bh=\frac{1}{2}\times10\times5\sqrt[]{3} \\ A=25\sqrt[]{3} \\ A=43.3\text{ square ft} \end{gathered}[/tex]Therefore, the area of the triangle is;
[tex]43.3\text{ square ft}[/tex]