we have the following:
[tex]a_n=\frac{11}{8}+\frac{1}{2}n[/tex]therefore, n = 23
[tex]\begin{gathered} a_{23}=\frac{11}{8}+\frac{1}{2}23 \\ a_{23}=\frac{11}{8}+\frac{23}{2} \\ a_{23}=\frac{11\cdot2+23\cdot8}{8\cdot2}=\frac{22+184}{16}=\frac{206}{16}=\frac{103}{8} \end{gathered}[/tex]the answer is 103/8