Answer :
We have the following:
[tex]\begin{gathered} 2x=3-4y \\ 4y=3-2x \\ \frac{4}{4}y=\frac{3}{4}-\frac{2}{4}x \\ y=\frac{3}{4}-\frac{1}{2}x \\ y=-\frac{1}{2}x+\frac{3}{4} \end{gathered}[/tex]replacing:
[tex]\begin{gathered} y=-\frac{1}{2}\cdot-4+\frac{3}{4} \\ y=2+0.75 \\ y=2.75 \end{gathered}[/tex]Which means that the equation does not contain that point