Answered

A light beam is shone into a mystery material . the light beam has an incident angle of 48 degree and a refracted angle of 27 degrees. If n1 = 1.00, what is n2? A) 1.78B) 0.56C) 1.64D) 0.61

Answer :

Given:

The incident angle is,

[tex]i=48\degree[/tex]

The refracted angle is

[tex]r=27\degree[/tex]

The refractive index of the first medium is,

[tex]n_1=1.00[/tex]

To find:

The refractive index of the second medium

[tex]n_2[/tex]

Explanation:

According to Snell's law,

[tex]\begin{gathered} n_1sini=n_2sinr \\ n_2=\frac{n_1sini}{sinr} \end{gathered}[/tex]

Substituting the values we get,

[tex]\begin{gathered} n_2=\frac{1.00\times sin48\degree}{sin27\degree} \\ =1.64 \end{gathered}[/tex]

Hence, the refractive index of the second medium is 1.64.

Other Questions