Answer :
Given
[tex]\begin{gathered} 10a+6b=8 \\ 5a+3b=2 \end{gathered}[/tex]We are to Solve by substitution or elimination.
Solution
Using Elimination method
[tex]\begin{gathered} 10a+6b=8\ldots Equation\text{ (i)} \\ 5a+\text{ 3b=2 }\ldots Equation(ii) \end{gathered}[/tex]Multiply the second equation by -2, then add the equations together.
[tex]\begin{gathered} 10a+6b=8 \\ -2(5a+3b=2) \\ \text{becomes} \\ 10a+6b=8 \\ -10a\text{ -6b=-4} \end{gathered}[/tex]Add these equations to eliminate a:
[tex]0=4[/tex]So the answer
No solutions.
Why it is no solution
A system has no solutions if two equations are parallel. ... When two equations have the same slope but different y-axis, they are parallel. Since there are no intersection points, the system has no solutions.