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Our subjects are 35-44-year-old males whose blood pressures are normally distributed with mean 80 and standard deviation 12;which we can denote by N(80, 12). A borderline hypertensive is defined as a person whose diastolic blood pressure is between 90 and 95 mm Hg inclusive; what proportion of subjects are borderline hypertensive? A hypertensive is a person whose diastolic blood pressure is above 95 mm Hg; what proportion of subjects are hypertensive?

Answer :

Given:

mean

[tex]\mu=80[/tex]

standard deviation

[tex]\sigma=12[/tex]

Required:

To defined as a person whose diastolic blood pressure is between 90 and 95 mm Hg inclusive; what proportion of subjects are borderline hypertensive.

For a person whose diastolic blood pressure is above 95 mm Hg; what proportion of subjects are hypertensive.

Explanation:

[tex]\begin{gathered} P(9095)=1-P(X\leq95) \\ =1-P(\frac{X-\mu}{\sigma}\leq\frac{95-80}{12}) \\ =1-P(Z\leq1.25) \\ =1-0.8944 \\ =0.1056 \end{gathered}[/tex]

Final Answer:

[tex]\begin{gathered} P(9095)=0.1056 \end{gathered}[/tex]

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