The following question has two parts. First, answer part A. Then, answer part B.Gabriel's father has a garden in the back yard. The dimensions of the garden are shown here.A green rectangle is shown. The width is labeled as 2 and two-thirds feet. The length is labeled as 7 and three-fourths feet.Part ACalculate the area of the garden. Show at least one step before you show your solution.Hello I need someone to guide my child through this problem can you please help me?

Answer :

Let us begin by writing out the given information:

The dimensions of the garden are:

[tex]\begin{gathered} \text{length}=\text{ 7}\frac{3}{4}\text{ ft} \\ \text{width = 2}\frac{2}{3}\text{ ft} \end{gathered}[/tex]

The area of the garden can be calculated using the formula:

[tex]\text{Area = length }\times\text{ width}[/tex]

Applying the formula using the given dimensions:

[tex]\begin{gathered} \text{Area = 7}\frac{3}{4}\text{ ft }\times\text{ 2}\frac{2}{3}\text{ ft} \\ =\text{ }\frac{31}{4}\text{ ft }\times\text{ }\frac{8}{3}\text{ ft} \\ =\text{ }\frac{62}{3}\text{ square f}eet \\ =\text{ 20}\frac{2}{3}\text{ square f}eet \end{gathered}[/tex]

Answer: 20 and two-thirds feet

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