Answer :
Given information:
Applied force,
[tex]F=10.0\text{ N}[/tex]Friction force,
[tex]f=8.0\text{ N}[/tex]Schematic diagram:
The net force acting on the box is given as,
[tex]F_{net}=F-f[/tex]Substituting all known values,
[tex]\begin{gathered} F_{net}=(10.0\text{ N})-(8.0\text{ N}) \\ =2.0\text{ N} \end{gathered}[/tex]Therefore, the sum of all of the forces on the box is 2.0 N.
