Answer :
[tex]\begin{gathered} f(x)=4x-3 \\ g(x)=x-\frac{3}{4} \\ \text{let use algebra to know if they are inverse} \\ (f\circ g)(x)=f(g(x)) \\ f(x-\frac{3}{4})=4(x-\frac{3}{4})-3=4x-3-3=4x-6 \\ \text{both are not inverses because i didn't end up getting x} \end{gathered}[/tex]