Hi I need help with this problem I need the salt for the distance for AC ADBDBCCDABRounded to the nearest hundredthI also need to know the steps of how to get those numbers


1) Let's begin by solving for the measures of the minor triangle
[tex]\Delta CDE[/tex]2) Let's use the Law of Sines to find CD, let's convert the measurements into decimal ones to better work:
[tex]\begin{gathered} 60^{\circ}06^{\prime}09^{\prime}^{\prime}=60°+06^{\prime}/60+09"/3600=60.1025^{\circ} \\ 97^{\circ}17^{\prime}42\~^{\prime}=97°+17^{\prime}/60+42"/3600=97.295° \end{gathered}[/tex][tex]\begin{gathered} \frac{CD}{\sin(60.1025)}=\frac{470.43}{\sin(97.295)} \\ CD\approx411.15 \end{gathered}[/tex]Let's find the angle D with the Triangle Sum Theorem:
[tex]60.1025+97.295+\angle D=180,\Rightarrow\angle D=22.6025^{\circ}[/tex]3) Looking back at the graph, we can find BC by finding the angle opposite to this side:
[tex]87^{\circ}20^{\prime}24^{\prime}^{\prime}=87°+20^{\prime}/60+24"/3600=87.34^{\circ}[/tex]Triangle sum theorem to help us find the angle opposite to BC:
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