Hi I need help with this problem I need the salt for the distance for AC ADBDBCCDABRounded to the nearest hundredthI also need to know the steps of how to get those numbers

Hi I need help with this problem I need the salt for the distance for AC ADBDBCCDABRounded to the nearest hundredthI also need to know the steps of how to get t class=
Hi I need help with this problem I need the salt for the distance for AC ADBDBCCDABRounded to the nearest hundredthI also need to know the steps of how to get t class=

Answer :

1) Let's begin by solving for the measures of the minor triangle

[tex]\Delta CDE[/tex]

2) Let's use the Law of Sines to find CD, let's convert the measurements into decimal ones to better work:

[tex]\begin{gathered} 60^{\circ}06^{\prime}09^{\prime}^{\prime}=60°+06^{\prime}/60+09"/3600=60.1025^{\circ} \\ 97^{\circ}17^{\prime}42\~^{\prime}=97°+17^{\prime}/60+42"/3600=97.295° \end{gathered}[/tex][tex]\begin{gathered} \frac{CD}{\sin(60.1025)}=\frac{470.43}{\sin(97.295)} \\ CD\approx411.15 \end{gathered}[/tex]

Let's find the angle D with the Triangle Sum Theorem:

[tex]60.1025+97.295+\angle D=180,\Rightarrow\angle D=22.6025^{\circ}[/tex]

3) Looking back at the graph, we can find BC by finding the angle opposite to this side:

[tex]87^{\circ}20^{\prime}24^{\prime}^{\prime}=87°+20^{\prime}/60+24"/3600=87.34^{\circ}[/tex]

Triangle sum theorem to help us find the angle opposite to BC:

[tex]undefined[/tex]

Other Questions