An equation has a slope of 22.4 and passes through the point ,(0.4, 25.3), what is the line equation of the line when written in point slope form and slope-intercept form?

Answer :

When we write a line equation, it can be written in point-slope form. This form is

[tex](y-y_1)=m(x-x_1)[/tex]

Where m represents the slope of the line, and (x1, y1) are the coordinates of a given point of the line.

Since we already have the slope and point, we can just substitute them on this form.

The line equation written in point-slope form is

[tex](y-25.3)=22.4(x-0.4)[/tex]

The slope-intercept form is

[tex]y=mx+b[/tex]

Where m represents the slope and b the y-intercept.

Since we already have the equation in point-slope form, we can just rewrite the equation

[tex]\begin{gathered} (y-25.3)=22.4(x-0.4) \\ y=22.4(x-0.4)+25.3 \\ y=22.4x-8.96+25.3 \\ y=22.4x+16.34 \end{gathered}[/tex]

And this is our equation in slope-intercept form

[tex]y=22.4x+16.34[/tex]

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