Answer :

The given expression is

[tex]4+\lbrack4(5-2)\rbrack\colon2[/tex]

First, we solve the difference inside the parenthesis.

[tex]4+\lbrack4(3)\rbrack\colon2[/tex]

Then, we solve the product inside the brackets.

[tex]4+\lbrack12\rbrack\colon2[/tex]

Then, we solve the division

[tex]4+6[/tex]

At last, we sum

[tex]10[/tex]

As you can observe, the equivalent expression is C, which we've got in the second step.

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