Answer :
Given:
[tex]x^4+2x^2-3=0[/tex]We will find the zeros of the function:
Factor the given function:
[tex]\begin{gathered} (x^2+3)(x^2-1)=0 \\ x^2-1=0\rightarrow x^2=1\rightarrow x=\pm1 \\ x^2+3=0\rightarrow x^2=-3\rightarrow x=\pm i\sqrt[]{3} \end{gathered}[/tex]So, there are four zeros
So, the answer will be:
[tex]x=\mleft\lbrace-1,1,i\sqrt[]{3},-i\sqrt[]{3}\mright\rbrace[/tex]