In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
triangle ABC:
CA = 10
AB = 8
CB = 6
triangle DEF:
FD = x
DE = 12
FE = y
Step 02:
similar triangles:
[tex]\begin{gathered} \frac{CA}{FD}=\frac{AB}{DE} \\ \frac{10}{x}=\frac{8}{12} \end{gathered}[/tex]10 * 12 = 8 * x
120 = 8x
120 / 8 = x
15 = x
[tex]\begin{gathered} \frac{CB}{FE}=\frac{AB}{DE} \\ \frac{6}{y}=\frac{8}{12} \end{gathered}[/tex]6 * 12 = 8 * y
72 = 8y
72 / 8 = y
9 = y
The answer is:
x = 15
y = 9