Answer :
[tex]x\text{ = 28}[/tex]
Here, we want to find the value of x in the diagram, given the value of the slope
From the question, we have two points, separated by a horizontal distance
Mathematiclly the slope of a line is;
[tex]\begin{gathered} m\text{ = }\frac{\Delta y}{\Delta x} \\ \\ m\text{ = }\frac{12-0}{\Delta x} \\ \\ \frac{1}{4}\text{ = }\frac{12}{\Delta x} \\ \\ \Delta x\text{ = 4}\times12 \\ \\ =\text{ 48} \end{gathered}[/tex]Now, what this mean is that, the x value from the tip of the triangle to the dotted line represented by 12 is 48
This is not the value of x, we want to calculate
Now, the x-distance from the tip of the rectangle to the dotted line marked as 5 is (48-x)
Thus, we have it that;
[tex]\begin{gathered} \frac{1}{4}\text{ = }\frac{5}{48-x} \\ \\ 4(5)\text{ = 48-x} \\ \\ 20\text{ = 48-x} \\ \\ x\text{ = 48-20} \\ \\ x\text{ = 28} \end{gathered}[/tex]