Answer :
Answer
t(d(n)) = 67 when n = 5
Explanation
t(d) = 3d + 1
d(n) = 4n + 2
t[d(n)] menas we evaluated t(d), but instead of d, we put in d(n)
t[d(n)] = 3[d(n)] + 1
= 3(4n + 2) + 1
= 12n + 6 + 1
= 12n + 7
when n = 5
t[d(n)] = 12n + 7 = 12(5) + 7 = 60 + 7 = 67
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