Answer :
The following parameters are given in the question
The zeros of the polynomial of degree 4 are given below as
[tex]\begin{gathered} -1(m\mu\text{ltiplicity of 2)} \\ it\text{ means that,} \\ x=-1 \\ (x+1) \\ \text{having a multiplicity of 2 will make it} \\ (x+1)^2 \end{gathered}[/tex]The other zeros given are
[tex]\begin{gathered} x=3 \\ (x-3)\text{ and } \\ x=0 \\ \end{gathered}[/tex]Multiplying all the factors to get the polynomial, we will have
[tex]\begin{gathered} f(x)=(x+1)^2(x-3)(x) \\ f(x)=(x+1)(x+1)(x-3)x \\ f(x)=x(x+1)^2(x-3) \end{gathered}[/tex]Hence,
F(x)= x(x-3)(x+1)²