To find the angle B we can use the sin lay so we know that:
[tex]\frac{\sin(B)}{b}=\frac{\sin (A)}{a}[/tex]so for our triangle will be:
[tex]\frac{\sin(B)}{28}=\frac{\sin (49)}{32}[/tex]and we solve for B so:
[tex]\begin{gathered} \sin (B)=\frac{28\sin (49)}{32} \\ B=\sin ^{-1}(0.66) \\ B=41.3 \end{gathered}[/tex]