#4 What is the equation of the line that passes through the points (3, 6) and (8, 14) ? Write the equation in point-slope form and slope-intercept form.

Answer :

slope-intercept form: y = 8x/5 + 1.2 or y = 1.6x + 1.2

point-slope form: y - 6 = 8/5(x - 3) or y - 6 = 1.6(x -3)

Explanation:

Given points (3, 6) and (8, 14) = (x1, y1) and (x2, y2)

We use the linear equation:

y = mx + c

m = slope and c = intercept

The slope formula:

[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\begin{gathered} m\text{ =}\frac{14-6}{8-3}\text{ = }\frac{8}{5} \\ m\text{ = 8/5} \end{gathered}[/tex]

We use any of the points given to find the intercept

using point (3, 6) , we insert in our linear equation:

6 = 8/5 (3) + c

6 = 24/5 + c

c = 6 - 24/5 = 6 - 4.8

c = 1.2

The linear equation becomes:

y = 8/5 (x) + 1.2

The slope intercept form: y = 8x/5 + 1.2 or y = 1.6x + 1.2

Point slope form:

[tex]y-y_1=m(x-x_1)[/tex]

using point (3, 6) = (x1, y1)

y - 6 = 8/5(x - 3) or

y - 6 = 1.6(x -3)

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