On a standardized exam, the scores are normally distributed with a mean of 550 anda standard deviation of 40. Find the Z-score of a person who scored 538 on the exam.Answer:Submit Answer

Answer :

For any normally distributed data, we can use the the formula for z-score as follows:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Where x is the data, in this case 538, μ is the mean, in this case 550, and σ is the standard deviation, in this case 40. z is the z-score.

So, we can just substitute our values and evaluate:

[tex]\begin{gathered} z=\frac{538-550}{40} \\ z=\frac{-12}{40} \\ z=-0.3 \end{gathered}[/tex]

Thus, the z-score is -0.3.

Other Questions