Answer :
Solution
For this case we have the following operation:
3x+7+89+28÷73×90
We apply the PEMDAS rule and we need to solve first Parenthesis, exponents, multiplication, division, addition and subtraction. And using this we have:
3x+7+89+28÷ 6570
[tex]\frac{3x+7+89}{\frac{28}{6570}}=\frac{3x+96}{\frac{28}{6570}}=\frac{6570(3x+96)}{28}[/tex]And that would be the final solution for this case