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What is the freezing point of a 0.800m aqueous solution of glucose, given that Kf for water is 1.86°C/m? Show your work.

Answer :

To determine the freezing point we can apply the following formula that relates the molality to the freezing point of water:

[tex]\Delta T_f=K_f\times m[/tex]

Where,

m is the molality

Kf is the freezing point of water

DeltaTf= Freezing point

We replace the known data:

[tex]\Delta T_f=1.86\frac{\degree C}{m}\times0.800m=1.49\degree C[/tex]

So, the freezing point of the solution will be 1.49°C

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