Answer :
Answer:
The solution to the System of equations is;
[tex]\begin{gathered} x=2 \\ y=-3 \end{gathered}[/tex]Explanation:
Given the System of Equations;
[tex]\begin{gathered} 3x-y=9 \\ 5x+y=7 \end{gathered}[/tex]Solving by elimination.
to eliminate y, let add equation 1 and 2 together;
[tex]\begin{gathered} 3x-y+5x+y=9+7 \\ 3x+5x-y+y=16 \\ 8x=16 \\ \text{divide both sides by 8;} \\ \frac{8x}{8}=\frac{16}{8} \\ x=2 \end{gathered}[/tex]Since we have the value of x let us now substitute into equation 2 to get the value of y;
[tex]\begin{gathered} 5x+y=7 \\ 5(2)+y=7 \\ 10+y=7 \\ y=7-10 \\ y=-3 \end{gathered}[/tex]Therefore, the solution to the System of equations is;
[tex]\begin{gathered} x=2 \\ y=-3 \end{gathered}[/tex]