Answer :
Given:
Diameter of cylinder = 0.26
Height of cylinder =1.2
Area of wallpaper is:
[tex]\begin{gathered} \text{Area}=2\pi rh \\ =2(\pi)(\frac{0.26}{2})(1.2) \\ =2\times\pi\times0.13\times1.2 \\ =0.98 \end{gathered}[/tex]So 0.98 wallpapere Rocio need