Solution
The figure contains a triangle. One side is 11 centimeters. A second side is 9 centimeters
To determine the area of the triangle
To find : Area of triangle .
Solution : We have given two sides to triangle = 11 cm , 9 cm .
Angle between two sides = 65 degree.
Where , a and b are two sides and C is angle between them .
Now, plugging the values
[tex]\begin{gathered} \theta=63 \\ a=11cm \\ b=9cm \end{gathered}[/tex][tex]\begin{gathered} \text{Area of the triangle = }\frac{1}{2}ab\sin \theta \\ A=\frac{1}{2}ab\sin \theta \\ A=\frac{1}{2}(11)(9)\sin 63 \\ A=\frac{99}{2}(0.8910) \\ A=49.5(0.8910) \\ A=44.104 \\ A\approx44.1\text{ (nearest tenth)} \end{gathered}[/tex]Therefore the area of this triangle = 44.1cm² ( nearest tenth)
