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Identify the number of solutions of the system of linear equations.x + 3y - z=2x+y-z=03x + 2y - 3z = -1• no solution• exactly one solution•infinitely many solutionsSolve the system using the elimination method. If there are infinitely many solutions, write the ordered triple in terms of z. If there is nosolution, leave each box empty.

Answer :

Given the equations:

[tex]\begin{gathered} x+3y-z=2\ldots\ldots.\ldots\ldots....\ldots\ldots\ldots\ldots\ldots\text{.}(1) \\ x+y-z=0\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots..\ldots..\ldots(2) \\ 3x+2y-3z=-1\ldots.\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots(3) \end{gathered}[/tex]

We want to solve them by elimination.

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