Answer :
Answer;
4.60moles
Explanations:
The number of moles and volume are related to each other by the formula;
[tex]\frac{n_1}{v_1}=\frac{n_2}{v_2}=k[/tex]where
n1 and n2 are the initial and final number of moles respectively
v1 and v2 are the initial and final volumes respectively
Given the following parameters
• n1 = 3.00moles
,• v1 = 550mL = 0.55L
,• v2 = 845mL = 0.845L
Required
Final mole "n2"
Substitute the given parameters into the formula
[tex]\begin{gathered} n_2=\frac{n_1v_2}{v_1} \\ n_2=\frac{3\times0.845}{0.55} \\ n_2=\frac{2.535}{0.55} \\ n_2=4.60moles \end{gathered}[/tex]Hence the number of moles will increase to 4.60moles