Answer :
[tex]\begin{gathered} 16H-4 \\ 4(4H-4) \end{gathered}[/tex]
we can multiply the factor on the second equation, then multipli 4H and -4 by 4
[tex]\begin{gathered} 4\times4H-4\times4 \\ 16H-16 \end{gathered}[/tex]the expressions arent equivalent
becuase 16H-16 is different to 16H-4