Answer :
Given:
[tex]\sin\theta=0.47[/tex][tex]0<\theta<90[/tex]Find-:
The value of
[tex]\cos\theta[/tex]Explanation-:
Use trignomertic formula:
[tex]\sin^2\theta+\cos^2\theta=1[/tex]So the value is:
[tex]\begin{gathered} \sin^2\theta+\cos^2\theta=1 \\ \\ \cos^2\theta=1-\sin^2\theta \\ \\ \cos\theta=\sqrt{1-\sin^2\theta} \end{gathered}[/tex]Given value of sin is:
[tex]\begin{gathered} \sin\theta=0.47 \\ \\ \sin^2\theta=(0.47)^2 \\ \\ \sin^2\theta=0.2209 \end{gathered}[/tex]So, the value is:
[tex]\begin{gathered} \cos\theta=\sqrt{1-\sin^2\theta} \\ \\ \cos\theta=\sqrt{1-0.2209} \\ \\ \cos\theta=\sqrt{0.7791} \\ \\ \cos\theta=0.883 \end{gathered}[/tex]So, the value is 0.883