Answer :
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
4x² + 6x = 18
Step 02:
quadratic formula:
4x² + 6x = 18
4x² + 6x - 18 = 0
a = 4
b = 6
c = - 18
[tex]x\text{ =}\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex][tex]x\text{ =}\frac{-6\pm\sqrt{(6)^2-4(4)(-18)}}{2(4)}=\frac{-6\pm\sqrt{36+288}}{8}=\frac{-6\pm\sqrt{324}}{8}[/tex][tex]\begin{gathered} x1\text{ = }\frac{-6+18}{8}=\frac{12}{8}=\frac{3}{2} \\ \\ x2=\frac{-6-18}{8}=\frac{-24}{8}=-3 \end{gathered}[/tex]The answer is:
x1 = 3 / 2
x2 = - 3