Given:
A circular piece of stock be to mill a hexagonal shape with a side length of 2.7 in.
Required:
We need to find the diameter of hexagon.
Explanation:
now use the sin function
[tex]\begin{gathered} sin30=\frac{1.35}{r} \\ \\ \frac{1}{2}=\frac{1.35}{r} \\ \\ r=2.7 \end{gathered}[/tex]so by r
[tex]d=2r=5.4\text{ in}[/tex]Final answer:
Diameter of hexagon is 5.4 in
