Write an equation (a) in slope-intercept form and (b) in standard form for the line passing through (-1,6) and parallel to x + 2y = 7.

Answer :

the line equation we want is parallel to x+2y=7, which means they have the same slope. Rewritting this function in the slope form

[tex]x+2y=7\Leftrightarrow y=-\frac{x}{2}+\frac{7}{2}[/tex]

The slope of our equation is (-1/2)!

Now, we just need to substitute the point to find the intercept.

[tex]\begin{gathered} y=-\frac{x}{2}+b \\ 6=-\frac{(-1)}{2}+b\Rightarrow b=\frac{11}{2} \end{gathered}[/tex]

Now we have the slope and the intercept. Solving item (a) and writing this function in slope-intercept form gives us

[tex]y=-\frac{x}{2}+\frac{11}{2}[/tex]

The standard form is:

[tex]Ax+By=C[/tex]

Rewriting our function like this, we get:

[tex]x+2y=11[/tex]

and this is the answer to item b.

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