Answer :
Let the no. of red rose be R,
Let the no. of pink rose be P.
$3*R+$2*P = $68
R+P=24
R=24-P
3(24-P)+2P=68
72-3P+2P=68
P=4
R=20
Let the no. of pink rose be P.
$3*R+$2*P = $68
R+P=24
R=24-P
3(24-P)+2P=68
72-3P+2P=68
P=4
R=20
Theres an idea on how to start you could solve by elimination or substitution!
