Answer :
The line equation is typically represented as
[tex]\begin{gathered} y=mx+b \\ \text{where} \\ m=\text{slope} \\ b=y-\text{intercept} \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-2-4}{4+4}=\frac{-6}{8}=-\frac{3}{4} \end{gathered}[/tex]Let find b
[tex]\begin{gathered} y=mx+b \\ 4=-\frac{3}{4}(-4)+b \\ b=1 \end{gathered}[/tex]The linear equation is
[tex]y=-\frac{3}{4}x+1[/tex]