Answer :
Explanation:
To find how many times is one number greater than another number we have to find the quotient between the two of them:
[tex]\frac{8\times10^5}{8\times10^{-1}}=\frac{8}{8}\times\frac{10^5}{10^{-1}}=10^{5-(-1)}=10^{5+1}=10^6[/tex]Answer:
8x10⁵ is 10⁶ times greater than 8x10⁻¹