What is the equation of the line that goes through (2, 2) and isperpendicular to y = 5x + 3?A. y-2=-1/5(x-2)B. y=-1/5(x+2)C. y-2 =5(x - 2)D. y-2=1/5(x-2)

Answer :

ANSWER:

A.

[tex]y-2=-\frac{1}{5}\cdot(x-2)[/tex]

STEP-BY-STEP EXPLANATION:

When two lines are perpendicular, the product of their slopes is equal to -1, therefore

[tex]\begin{gathered} m_1\cdot m_2=-1 \\ 5\cdot m_2=-1 \\ m_2=-\frac{1}{5} \end{gathered}[/tex]

We have that the equation in its slope and point form is the following:

[tex]y-y_1=m\cdot(x-x_1)[/tex]

We replace the values of the point and the slope and we would have the following equation

[tex]y-2=-\frac{1}{5}\cdot(x-2)[/tex]