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For the geometric series shown, a₁=1/2 and r=1/2.
1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64
Study the work shown to find the partial sum for these 6 terms.
S₆=1/2 [1-( 1/2 )6]/1- 1/2 = 1/2 [ 1- 1/64 ] / 1/2 = 1/2 [ 63/64 ] / 1/2 = 63/64

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