Answered

Find the values of​ a, b, and c for which the quadratic equation ax^2 + bx + c = 0 has the solutions 8i and −8i.

Answer :

altavistard
Work backward:  Multiply out (x-8i) and (x+8i).

The product is x^2 - [64i^2], or x^2 - [-64], or x^2 + 64

This is equivalent to 1x^2 + 0x + 64, and so a=1, b=0 and c=64.

Other Questions