Answer :
Width= x
Length: 80+x
p=2(l+w)
320=2(80+x+x)
320=2(80+2x)
320=160+4x
320-160=4x
160=4x
160/4=x
40yd=x
The width is 40 yds and the length is 80+40=120 yards
Hope I helped :)
Length: 80+x
p=2(l+w)
320=2(80+x+x)
320=2(80+2x)
320=160+4x
320-160=4x
160=4x
160/4=x
40yd=x
The width is 40 yds and the length is 80+40=120 yards
Hope I helped :)
The dimensions of a rectangular field is width = 40 yd and length = 120 yd.
What is a rectangle?
A rectangle is one of the types of quadrilaterals in which all four angles are right angles or equal to 90 degrees. It is four-sided polygon in which the opposite sides are parallel and equal to each other.
For the given situation,
Let the width of the rectangle, w = x
The length is 80 yd longer than the width.
The length of the rectangle, l = x + 80.
The perimeter of a rectangular field = 320 yd.
The formula of perimeter of rectangle is
[tex]P=2(w+l)[/tex]
On substituting the above values,
⇒ [tex]320=2(x+x+80)[/tex]
⇒ [tex]320=2(2x+80)[/tex]
⇒ [tex]2x+80=\frac{320}{2}[/tex]
⇒ [tex]2x+80=160[/tex]
⇒ [tex]2x=160-80[/tex]
⇒ [tex]2x=80[/tex]
⇒ [tex]x=\frac{80}{2}[/tex]
⇒ [tex]x=40[/tex]
Thus width = [tex]40[/tex] and
length = [tex]40+80[/tex]
⇒ [tex]120[/tex]
Hence we can conclude that the dimensions of a rectangular field is width = 40 yd and length = 120 yd.
Learn more about the rectangles here
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