In part a, we saw that the theoretical yield of aluminum oxide is 1.40 mol . calculate the percent yield if the actual yield of aluminum oxide is 0.938 mol .

Answer :

Kalahira
1.4 moles of aluminium metal is exposed to 1.35 mol of oxygen Theoretical yield=0.007 mol calculate % yield % yield= actual yield/theoretical yield*100 % yield= 0.938/0.700*100 % yield= 13.4% yield

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