Answer :
This pattern would be exponential.
Lets look at it.
0.7 x 3 = 2.1
2.1 x 3 = 6.3
6.3 x 3 = 18.9
The first term 0.7 is essentially 0.7 x zero 3's (0.7)
The second term is 0.7 x one 3 (0.7 x 3)
The third term is 0.7 x two 3's (0.7 x 3 x 3)
The fourth term is 0.7 x three 3's (0.7 x 3 x 3 x 3)
We can write a mathematical equation to describe this pattern:
f(x) = 0.7(3)^(x-1)
Lets see if this actually gives us the right values.
First term: x = 1
Second term: x = 2
Third term: x = 3
Fourth term:x = 4
First term: f(1) = 0.7(3)^(1-1) = 0.7(3)^0 = 0.7 (3^0 simply becomes 1)
Second term: f(2) = 0.7(3)^(2-1) = 0.7(2)^1 = 0.7 x 3 = 2.1
Third term: f(3) = 0.7(3)^(3-1) = 0.7(3)^2 = 0.7 x 3 x 3 = 6.3
Fourth term: f(4) = 0.7(3)^(4-1) = 0.7(3)^3 = 0.7 x 3 x 3 x 3 = 18.9
As you can see, this function outputs the same values in the pattern.
This function, f(x) = 0.7(3)^(x-1), is indeed an exponential function, so the pattern formed by this function is an exponential pattern.
Lets look at it.
0.7 x 3 = 2.1
2.1 x 3 = 6.3
6.3 x 3 = 18.9
The first term 0.7 is essentially 0.7 x zero 3's (0.7)
The second term is 0.7 x one 3 (0.7 x 3)
The third term is 0.7 x two 3's (0.7 x 3 x 3)
The fourth term is 0.7 x three 3's (0.7 x 3 x 3 x 3)
We can write a mathematical equation to describe this pattern:
f(x) = 0.7(3)^(x-1)
Lets see if this actually gives us the right values.
First term: x = 1
Second term: x = 2
Third term: x = 3
Fourth term:x = 4
First term: f(1) = 0.7(3)^(1-1) = 0.7(3)^0 = 0.7 (3^0 simply becomes 1)
Second term: f(2) = 0.7(3)^(2-1) = 0.7(2)^1 = 0.7 x 3 = 2.1
Third term: f(3) = 0.7(3)^(3-1) = 0.7(3)^2 = 0.7 x 3 x 3 = 6.3
Fourth term: f(4) = 0.7(3)^(4-1) = 0.7(3)^3 = 0.7 x 3 x 3 x 3 = 18.9
As you can see, this function outputs the same values in the pattern.
This function, f(x) = 0.7(3)^(x-1), is indeed an exponential function, so the pattern formed by this function is an exponential pattern.