Answer :
[tex]a_1=-1[/tex]
[tex]a_2=\dfrac{a_1}{2+1}=-\dfrac13[/tex]
[tex]a_3=\dfrac{-\frac13}{3+1}=-\dfrac1{3\times4}=-\dfrac1{12}[/tex]
[tex]a_4=\dfrac{-\frac1{12}}{4+1}=-\dfrac1{12\times5}=-\dfrac1{60}[/tex]
[tex]a_2=\dfrac{a_1}{2+1}=-\dfrac13[/tex]
[tex]a_3=\dfrac{-\frac13}{3+1}=-\dfrac1{3\times4}=-\dfrac1{12}[/tex]
[tex]a_4=\dfrac{-\frac1{12}}{4+1}=-\dfrac1{12\times5}=-\dfrac1{60}[/tex]