Answer :
Answer:
Time taken to stop = 5.94 seconds
Explanation:
We have equation of motion, v = u + at
Final velocity , v = 0 m/s
Initial velocity, u = 19 m/s
Acceleration, a = -3.2 m/s²
time, t = ?
Substituting
0 = 19 - 3.2 x t
t = 5.94 s
Time taken to stop = 5.94 seconds