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If ΔABC is dilated by a scale factor of 1/2

with a dilation center of A, what will be the coordinates of point C'?
A) (0, 0)
B) (1, 0)
C) (0, 1)
D) (4, 0)

If ΔABC is dilated by a scale factor of 1/2 with a dilation center of A, what will be the coordinates of point C'? A) (0, 0) B) (1, 0) C) (0, 1) D) (4, 0) class=

Answer :

Point C is at (2,0)

Cut each coordinate in half to get (1,0)
2*(1/2) = 1
0*(1/2) = 0

So point C will move to (1,0)

Answer: Choice B)

Answer:  The correct option is (B) (1, 0).

Step-by-step explanation:  Given that ΔABC is dilated by a scale factor of [tex]\dfrac{1}{2}[/tex] with the center of dilation at the point A.

Let, the dilated triangle be ΔA'B'C'.

We are to find the co-ordinates of the point C'.

From the figure, we note that

the co-ordinates of the vertices of ΔABC are A(0, 0), B(0, 3) and C(2, 0).

Since the center of dilation is at the origin, so the co-ordinates of each vertex after dilation will be

[tex]A(0,0)\rightarrow A'\left(\dfrac{0}{2},\dfrac{0}{2}\right)=A'(0,0),\\\\B(0,3)\rightarrow B'\left(\dfrac{0}{2},\dfrac{3}{2}\right)=B'(0,1.5),\\\\C(0,0)\rightarrow C'\left(\dfrac{2}{2},\dfrac{0}{2}\right)=C'(1,0).[/tex]

Thus, the co-ordinates of point C' are (1, 0).

Option (B) is correct.

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