Answer :
Answer: $80, $221 (Option B)
WORKINGS
Mia worked 2 part time jobs for a total of 25 hours per week.
Assume,
She works on the first Job for x hours
She works on the second job for y hours
Then x + y = 25 (Equation I)
We are told that in a week, she earned $301
This pay is represented by the equation 10x + 13y = 301 (Equation II)
Now, we have:
x + y = 25 (Equation I)
10x + 13y = 301 (Equation II)
Solving for x and y;
Divide equation 2 by 10
10x + 13y = 301 (Equation II)
10x/10 + 13y/10 = 301/10
x + 1.3y = 30.1 (Equation III)
Subtract Equation I from Equation III
x + 1.3y – (x + y) = 30.1 – 25
x + 1.3y – x – y = 5.1
Collect like terms’
x – x + 1.3y – y = 5.1
0.3y = 5.1
Divide through by 0.3
0.3y/0.3 = 5.1/0.3
y = 17
Substitute 17 for y in equation I
x + y = 25 (Equation I)
y = 17
x + 17 = 25
Subtract 17 from both sides of the equation
x + 17 – 17 = 25 – 17
x = 8
Therefore,
x = 8, y = 17
This means that,
She works on the first Job for 8 hours
She works on the second job for 17 hours
Now, her pay is represented by the equation 10x + 13y = 301
This means,
She is paid $10 per hour on the first job
She is paid $13 per hour on the second job
If she is paid $10 per hour on the first job
She works on the first Job for 8 hours
This means, she earned $10 x 8 on the first Job
= $80
If she is paid $13 per hour on the second job
She works on the second job for 17 hours
This means, she earned $13 x 17 on the second Job
= $221
The answer is $80, $221 (Option B)