Answer :
For this case the new area is the sum of two areas:
Area = rectangular gym + weight room
Area = (4x² + 520) ft²
In addition, we know that
rectangular gym = 4x ^ 2 ft²
Therefore, the term 520 represents a new weight room
answer
The constant term represent a new weight room
Area = rectangular gym + weight room
Area = (4x² + 520) ft²
In addition, we know that
rectangular gym = 4x ^ 2 ft²
Therefore, the term 520 represents a new weight room
answer
The constant term represent a new weight room
Answer:
The constant term represent the area of the weight room
Step-by-step explanation:
Let
R-----> the area of the rectangular gym
W-----> the area of the weight room
A-----> the area total
we know that
[tex]A=R+W[/tex]
In this problem we have
[tex]R=4x^{2}\ ft^{2}[/tex]
[tex]A=(4x^{2}+520)\ ft^{2}[/tex]
substitute in the formula above and solve for W
[tex](4x^{2}+520)=4x^{2}+W[/tex]
[tex]W=520\ ft^{2}[/tex]
therefore
The constant term W represent the area of the weight room