Answer :

jongdae21
Is BC=2.3 one of the options?

For that question, you can use the cosine rule, where;
[tex]{a}^{2} = {b}^{2} + {c}^{2} - 2(b)(c) \cos( \alpha ) [/tex]
In this case, we have..
[tex] {bc}^{2} = {1.8}^{2} + {2.1}^{2} - 2(1.8)(2.1) \cos(70) [/tex]
Solving for BC with this will get you 2.250406, rounded off to the tenth is 2.3.

Answer:

BC = 2.3

Step-by-step explanation:

Given  : A triangle With side AB = 1.8 , AC = 2.1 and angle = 70 degree.

To find : Find BC .

Solution : We have given

AB = 1.8 , AC = 2.1

Angle = 70 degree.

By the cosine rule : The third side of a triangle when we know two sides and the angle between them.

BC² = AB² + AC² − 2AB(AC) cos(A).

Plug the values AB = 1.8 , AC = 2.1

BC² = (1.8)² + (2.1)² − 2(1.8)(2.1)cos(70)

 BC² = 3.24 + 4.41 - 7.56 ( 0.34).

BC²   = 3.24 + 4.41 - 2.5704

  BC² = 5.0796.

Taking square root

BC = √ 5.0796.

BC = 2.25

Nearest tenth = 2.3

Therefore, BC = 2.3

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