Answer :
Answer: The correct answer is 70.54%.
The first thing to do is find the z-score for precipitation over 18 inches. You have to subtract the value from the mean and divide by the standard deviation.
18 - 19.32 = -1.32 / 2.44 = -0.54
Now, just look up the z-score of -0.54 on a standard normal distribution table and you will see that 29.46% of the scores are below 18 inches. Therefore, there are 70.54% scores above 18 inches.
The first thing to do is find the z-score for precipitation over 18 inches. You have to subtract the value from the mean and divide by the standard deviation.
18 - 19.32 = -1.32 / 2.44 = -0.54
Now, just look up the z-score of -0.54 on a standard normal distribution table and you will see that 29.46% of the scores are below 18 inches. Therefore, there are 70.54% scores above 18 inches.