Hi there! The answer is D.
The volume of this cylinder can be found with the formula
[tex]v = \pi \: r {}^{2} \: h[/tex]
With r representing the radius.
The smaller can (with radius 1 and height 3), therefore has a volume of
[tex]v = \pi \times 1 {}^{2} \times 3 = 3\pi[/tex]
The larger can (with a radius of 2 × 1 = 2 and a height of 2 × 3 = 6), therefore has a volume of
[tex]v = \pi \times 2 {}^{2} \times 6 = 24\pi[/tex]
[tex]24\pi = 8 \times 3\pi[/tex]
And therefore answer D. is correct: The volume of the large trash can is eight times the volume of the small trash can.
